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4u^2+21u-18=0
a = 4; b = 21; c = -18;
Δ = b2-4ac
Δ = 212-4·4·(-18)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-27}{2*4}=\frac{-48}{8} =-6 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+27}{2*4}=\frac{6}{8} =3/4 $
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